Question Statement
Evaluate the integral:
∫21(cosec2x−cosecxcotx)dx
Background and Explanation
This problem requires standard integration formulas for trigonometric functions involving cosecant, along with the linearity properties of integrals (constant multiple rule and difference rule).
Solution
Let
I=∫21(cosec2x−cosecxcotx)dx
Using the constant multiple rule, we factor out 21, and then apply the difference rule to split the integral:
=21∫cosec2xdx−21∫cosecxcotxdx
Now we apply the standard integration formulas. Recall that ∫cosec2xdx=−cotx and ∫cosecxcotxdx=−cosecx:
=21(−cotx)−21(−cosecx)+c
Simplifying the expression by distributing the negative signs:
=2−1cotx+21cosecx+c
To confirm our answer is correct, we differentiate the result:
dxd(2−1cotx+21cosecx+c)
=2−1dxd(cotx)+21dxd(cosecx)+dxd(c)
=2−1(−cosec2x)+21(−cosecxcotx)+0
=21cosec2x−21cosecxcotx
=21(cosec2x−cosecxcotx)
Since differentiation yields the original integrand, the solution is verified.
- ∫cosec2xdx=−cotx+c
- ∫cosecxcotxdx=−cosecx+c
- Constant multiple rule: ∫k⋅f(x)dx=k∫f(x)dx
- Difference rule: ∫[f(x)−g(x)]dx=∫f(x)dx−∫g(x)dx
- Derivative verification: dxd(cotx)=−cosec2x and dxd(cosecx)=−cosecxcotx
Summary of Steps
- Factor out the constant 21 from the integral using the constant multiple rule
- Split the integral into two separate integrals using the difference rule
- Apply the standard integral ∫cosec2xdx=−cotx to the first term
- Apply the standard integral ∫cosecxcotxdx=−cosecx to the second term
- Simplify the signs to obtain −21cotx+21cosecx+c
- Verify the result by differentiating to recover the original integrand