Question Statement
Evaluate the integral:
∫[1−8cosec2(2x)]dx
Background and Explanation
This problem requires applying the linearity property of integrals to separate the expression into simpler terms, along with the standard integral formula for cosec2(ax). The solution can be verified by differentiation using the chain rule.
Solution
Let I denote the integral:
I=∫(1−8cosec22x)dx
Using the linearity property of integration, we split this into two separate integrals:
I=∫1dx−8∫cosec22xdx
Evaluating each part:
- The integral of 1 with respect to x is x
- For the second integral, we apply the standard formula ∫cosec2(ax)dx=a−cot(ax)
With a=2:
I=x−8(2−cot2x)+c
Simplifying the coefficient (−8×−21=4):
I=x+4cot2x+c
To confirm the answer, we differentiate the result:
dxd(x+4cot2x+c)
Applying the sum rule and differentiating term by term:
=dxd(x)+dxd(4cot2x)+dxd(c)
=1+4dxd(cot2x)+0
Using the chain rule for cot(2x), where the derivative of cot(u) is −cosec2(u) and the derivative of 2x is 2:
=1+4(−cosec22x)⋅2
=1−8cosec22x
This matches the original integrand, confirming the solution is correct.
- Linearity of Integration: ∫[f(x)−g(x)]dx=∫f(x)dx−∫g(x)dx
- Standard Integral: ∫cosec2(ax)dx=−acot(ax)+C
- Chain Rule: dxd[cot(ax)]=−acosec2(ax)
- Basic Integral: ∫1dx=x+C
Summary of Steps
- Apply linearity to split the integral: ∫1dx−8∫cosec2(2x)dx
- Integrate the first term to obtain x
- Use the standard formula for ∫cosec2(ax)dx with a=2 to get −2cot(2x)
- Simplify the constants: −8×(−2cot(2x))=4cot(2x)
- Combine and add constant of integration: x+4cot(2x)+c
- Verify by differentiation using the chain rule to ensure the derivative equals 1−8cosec2(2x)