This section covers constructing matrices from formulas, performing matrix operations, and proving matrix identities — all core skills for FBISE Grade 11 Mathematics.
A matrix A = [ a ij ] of order m × n can be defined by giving a formula for each element a ij , where:
i = row number (1 ≤ i ≤ m )
j = column number (1 ≤ j ≤ n )
Construct a 2 × 3 matrix B = [ b ij ] where b ij = 3 i 2 − j .
Calculate each element by substituting the appropriate i and j :
b 11 = 3 1 − 1 = 0 , b 12 = 3 1 − 2 = − 3 1 , b 13 = 3 1 − 3 = − 3 2
b 21 = 3 4 − 1 = 1 , b 22 = 3 4 − 2 = 3 2 , b 23 = 3 4 − 3 = 3 1
B = 0 1 − 3 1 3 2 − 3 2 3 1
For matrices A (of order m × n ) and B (of order n × p ), the product A B is an m × p matrix where:
( A B ) ij = ∑ k = 1 n a ik b k j
Key properties:
Matrix multiplication is not commutative in general: A B = B A
It is associative : ( A B ) C = A ( B C )
It is distributive : A ( B + C ) = A B + A C
To solve A X B = C for unknown matrix X (where A and B are invertible):
Pre-multiply both sides by A − 1 : X B = A − 1 C
Post-multiply both sides by B − 1 : X = A − 1 C B − 1
⚠️ Order matters! A − 1 C B − 1 = A − 1 B − 1 C in general.
The transpose of a matrix A , written A T , is obtained by swapping rows and columns.
Key properties:
Property Rule Double transpose ( A T ) T = A Sum ( A + B ) T = A T + B T Scalar multiple ( k A ) T = k A T Product (reverse order) ( A B ) T = B T A T
The product rule extends: ( A B C ) T = C T B T A T .
Given conditions like A B = B and B A = A , we can simplify powers of matrices:
Simplifying A 2 :
A 2 = A ⋅ A = A ( B A ) = ( A B ) A = B ⋅ A = A
Simplifying B 2 :
B 2 = B ⋅ B = B ( A B ) = ( B A ) B = A ⋅ B = B
Therefore: A 2 + B 2 = A + B
To verify an identity like X 2 − 4 X − 5 I = O for a given matrix X :
Compute X 2 by matrix multiplication.
Compute 4 X by scalar multiplication.
Note: the constant 5 must be written as 5 I (where I is the identity matrix of the same order as X ) to allow matrix subtraction.
Substitute and simplify to show the result is the zero matrix O .
To prove a formula for A n for all positive integers n :
Base case (n = 1 ): Verify the formula holds for A 1 = A .
Inductive hypothesis : Assume the formula holds for n = k , i.e., assume A k = [formula] .
Inductive step : Show it holds for n = k + 1 by computing A k + 1 = A k ⋅ A and using the hypothesis.
Operation Rule Matrix element a ij : row i , column j Product transpose ( A B ) T = B T A T Solving A X B = C X = A − 1 C B − 1 Scalar in matrix equation Replace constant c with c I Proving A n Use Mathematical Induction