In this type of question, a matrix A = [ a ij ] of a given order m × n is constructed by substituting values of i (row index) and j (column index) into a given formula for the general element a ij .
Key notation:
i = row number, 1 ≤ i ≤ m
j = column number, 1 ≤ j ≤ n
a ij = element at row i , column j
Identify the order of the matrix (e.g., 2 × 3 means 2 rows, 3 columns).
For each position ( i , j ) , substitute the values into the formula to find a ij .
Arrange the computed values into the matrix.
Construct a 2 × 3 matrix A = [ a ij ] where a ij = 2 i − j .
The matrix has m = 2 rows and n = 3 columns. Compute each element:
j = 1 j = 2 j = 3 i = 1 a 11 = 2 ( 1 ) − 1 = 1 a 12 = 2 ( 1 ) − 2 = 0 a 13 = 2 ( 1 ) − 3 = − 1 i = 2 a 21 = 2 ( 2 ) − 1 = 3 a 22 = 2 ( 2 ) − 2 = 2 a 23 = 2 ( 2 ) − 3 = 1
So:
A = [ 1 3 0 2 − 1 1 ]
Construct a 2 × 2 matrix B = [ b ij ] where b ij = 3 i 2 − j .
Compute each element:
b 11 = 3 1 − 1 = 0 , b 12 = 3 1 − 2 = − 3 1
b 21 = 3 4 − 1 = 1 , b 22 = 3 4 − 2 = 3 2
So:
B = 0 1 − 3 1 3 2