The ethane molecule consists of two carbon atoms bonded to each other by a single covalent bond. Each carbon atom is also bonded to three hydrogen atoms by single covalent bonds. A covalent bond formed by the direct, end-on overlap of atomic orbitals is called a sigma () bond. All single covalent bonds in ethane are sigma bonds.
Each carbon atom in ethane undergoes hybridization. Consequently, all orbitals involved in bonding, both C-C and C-H bonds, are hybridized orbitals. For more on how these orbitals are formed, see Shapes of Orbitals→.
The ethane molecule is non-planar. The covalent bonds around each carbon atom are arranged in a tetrahedral geometry. This arrangement results in bond angles of approximately between any two bonds on the same carbon atom.

The cyclopropane molecule consists of three carbon atoms bonded by single covalent bonds to form a triangular ring. Each carbon atom is also bonded to two hydrogen atoms.
Like ethane, each carbon atom in cyclopropane exhibits hybridization. The orbitals involved in C-C and C-H bonds are hybridized, which ideally leads to a tetrahedral arrangement.
The molecule has a three-dimensional, non-planar structure. The C-C-C bond angle within the ring is constrained to . This is a significant deviation from the ideal angle for hybridized orbitals, causing substantial angle strain (also called ring strain).
Because the orbitals cannot overlap head-on effectively due to the geometric constraints of the ring, the C-C bonds are often described as 'bent bonds' or 'banana bonds'.
The H-C-H and C-C-H bond angles are closer to the ideal tetrahedral angle of .
Due to the high angle strain from the C-C-C bond angle (vs. ideal ), the bent bonds in cyclopropane are weaker than normal bonds. This makes cyclopropane significantly more reactive than other alkanes such as ethane, and it can undergo ring-opening reactions.

Derived from FBISE Textbook for Class 11 Chemistry, Chapter 16: Hydrocarbons.