Prove that $\cot 2x = \frac{\sin x - \sin 3x}{\cos 3… |

Q15Short4 marks2022 · Annual

Question

\cot 2x = \frac{\sin x - \sin 3x}{\cos 3x - \cos x}\text{.}

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Apply fundamental law and its deductions to derive: Trigonometric ratios of allied angles, double angle, half angle and triple angle identities.

Express the product (of sines and cosines) as sums or differences (of sines and cosines).