A farmer owns a triangular shaped piece of land with corners at X(3,7), Y(6,2) and Z(10,8). Calculate the cost of planting maize crop @ Rs. 300 per square unit.
Background and Explanation
This problem requires finding the area of a triangle given its vertices using coordinate geometry (determinant method), then applying a per-unit rate to determine the total cost of cultivation.
Solution
First, we find the area of the triangular field XYZ using the determinant formula for the area of a triangle with vertices (x1,y1), (x2,y2), and (x3,y3).
Area of triangle XYZ=213610728111
Expanding the determinant along the first row using cofactors:
=21(32811−761011+161028)
Evaluating each 2×2 determinant:
=21(3(2−8)−7(6−10)+1(48−20))
Simplifying the expressions inside the parentheses:
=21(−18+28+28)
=19 sq. units
Thus, the cost of planting maize @ Rs. 300 per square unit is:
Cost=19×300=Rs. 5700
Key Formulas or Methods Used
Area of triangle using determinant: Area=21x1x2x3y1y2y3111
Cofactor expansion: Expanding a 3×3 determinant along the first row
Total cost formula: Cost=Area×Rate per square unit
Summary of Steps
Identify coordinates: Note the vertices X(3,7), Y(6,2), and Z(10,8)
Set up the determinant: Construct the 3×3 matrix with x-coordinates in the first column, y-coordinates in the second, and 1s in the third
Expand the determinant: Apply cofactor expansion along the first row to reduce to 2×2 determinants
Evaluate minors: Calculate each 2×2 determinant (e.g., (2−8), (6−10), (48−20))
Compute the area: Multiply the sum by 21 to obtain 19 square units
Calculate total cost: Multiply the area (19) by the rate (Rs. 300) to get Rs. 5700