Question Statement
Solve the differential equation:
(sinx+cosx)dx=cotycosxdy
Background and Explanation
This is a first-order ordinary differential equation that can be solved using the method of separation of variables. The goal is to algebraically rearrange the equation so that all terms involving x and dx appear on one side, while all terms involving y and dy appear on the other side, allowing us to integrate both sides independently.
Solution
Begin with the given differential equation:
(sinx+cosx)dx=cotycosxdy
To separate the variables, divide both sides by cosx (assuming cosx=0):
(cosxsinx+cosx)dx=cotydy
Now integrate both sides of the equation:
∫cosxsinx+cosxdx=∫cotydy
Decompose the fraction on the left side by splitting the numerator:
∫(cosxsinx+cosxcosx)dx=∫cotydy
Simplify the terms inside the integral. Note that cosxsinx=tanx and cosxcosx=1:
∫tanxdx+∫1dx=∫cotydy
Evaluate each integral using standard formulas:
- ∫tanxdx=ln(secx)
- ∫1dx=x
- ∫cotydy=ln(siny)
Applying these results and adding the constant of integration c:
ln(secx)+x=ln(siny)+c
This is the general solution to the differential equation. If an initial condition were provided (such as y(x0)=y0), you could substitute these values to solve for the specific constant c and obtain the particular solution.
(Note: The solution can also be expressed in explicit form by exponentiating: siny=secx⋅ex−c, or equivalently y=arcsin(Kcosxex) where K=ec.)
- Separation of variables: Rearranging M(x)dx=N(y)dy form
- Algebraic decomposition: cosxsinx+cosx=tanx+1
- Integral of tangent: ∫tanxdx=ln(secx)+C (or −ln∣cosx∣+C)
- Integral of cotangent: ∫cotydy=ln(siny)+C (or ln∣siny∣+C)
- Constant of integration: Added as +c (or +C) when performing indefinite integration
Summary of Steps
- Separate variables: Divide both sides by cosx to isolate x-terms on the left and y-terms on the right
- Simplify: Break cosxsinx+cosx into tanx+1
- Set up integrals: Write ∫(tanx+1)dx=∫cotydy
- Integrate: Apply standard integral formulas to get ln(secx)+x=ln(siny)+c
- General solution: The implicit equation ln(secx)+x=ln(siny)+c represents the family of all solutions; substitute initial values if given to find the specific constant c