This problem involves integrating exponential functions where the exponent contains a linear function of x (i.e., ax form). You will apply the standard integration formula for eax and evaluate the result using the Fundamental Theorem of Calculus.
Solution
We solve this by applying the linearity property of integrals and the exponential integration formula.
Step 1: Use linearity to split the integral into two separate integrals:
∫24(e2x−e4x)dx=∫24ex/2dx−∫24ex/4dx
Step 2: Apply the integration formula ∫eaxdx=aeax to each term.
For the first integral, a=21, so the antiderivative is 1/2ex/2=2ex/2.
For the second integral, a=41, so the antiderivative is 1/4ex/4=4ex/4.
Using evaluation notation F(x)∣ab to denote F(b)−F(a):
=1/2ex/224−1/4ex/424(Formula: ∫eaxdx=aeax)
Simplify the constant coefficients:
=2ex/224−4ex/424
Step 3: Evaluate at the upper limit (x=4) and lower limit (x=2):
=2(e4/2−e2/2)−4(e4/4−e2/4)
Simplify the exponents:
=2(e2−e)−4(e−e1/2)
Step 4: Distribute the coefficients and combine like terms:
=2e2−2e−4e+4e1/2
=2e2−6e+4e1/2
Therefore, the value of the integral is 2e2−6e+4e.
Key Formulas or Methods Used
Linearity of Integration:∫(f(x)−g(x))dx=∫f(x)dx−∫g(x)dx
Exponential Integration:∫eaxdx=aeax+C (for a=0)
Fundamental Theorem of Calculus:∫abf(x)dx=F(x)∣ab=F(b)−F(a)
Evaluation Notation:F(x)∣ab represents the antiderivative evaluated from a to b
Summary of Steps
Separate the integral into two parts using the difference rule for integration
Integrate each exponential using the formula ∫eaxdx=aeax, giving coefficients 2 and 4 respectively
Apply the limits by substituting x=4 and x=2 into each antiderivative and subtracting (upper minus lower)
Simplify algebraically by distributing the constants and combining the e terms to get the final answer 2e2−6e+4e1/2