Question Statement
Find the slope of the tangent line to the function f(x)=−21x+3 at the point (a,f(a)) using the limit definition of the derivative.
Background and Explanation
This problem applies the limit definition of the derivative to find the slope of a tangent line to a linear function. The limit definition calculates the instantaneous rate of change by evaluating the limit of the difference quotient as the interval Δx approaches zero.
Solution
Given the function:
f(x)=−21x+3
First, we evaluate the function at x+Δx:
f(x+Δx)=−21(x+Δx)+3
The slope of the tangent line is defined by the limit:
mtan=limΔx→0Δxf(x+Δx)−f(x)
Substituting our expressions for f(x+Δx) and f(x):
mtan=limΔx→0Δx(−21(x+Δx)+3)−(−21x+3)
Expanding the numerator:
=limΔx→0Δx−21x−21Δx+3+21x−3
Simplifying by combining like terms (the −21x and +21x cancel, as do the +3 and −3):
=limΔx→0Δx−21Δx
Canceling Δx from the numerator and denominator:
=limΔx→0(−21)
Evaluating the limit (since the expression no longer depends on Δx):
mtan=−21
Therefore, the slope of the tangent line at any point (a,f(a)) is −21.
- Limit definition of the derivative (slope of tangent): mtan=limΔx→0Δxf(x+Δx)−f(x)
- Function substitution: Evaluating f(x+Δx) by replacing x with (x+Δx) in the function expression
Summary of Steps
- Identify the given function f(x)=−21x+3
- Calculate f(x+Δx) by substituting (x+Δx) into the function
- Set up the limit definition of the derivative (the difference quotient)
- Substitute both f(x+Δx) and f(x) into the numerator
- Expand and simplify the numerator by distributing and combining like terms
- Cancel Δx from the numerator and denominator
- Evaluate the limit as Δx→0 to obtain the slope −21