2.1 Q-8

Q8. ${\lim }_{x\to 3}\frac{(x+3{)}^2}{\sqrt{x-3}}$

\section*{Solution:} $\begin{array}{rl}& \underset{x\to 3}{\lim }\frac{(x+3{)}^2}{\sqrt{x-3}}\\ & =\frac{(3+3{)}^2}{\sqrt{3-3}}\\ & =\frac{(6{)}^2}{\sqrt{0}}\\ & =\frac{36}{0}\\ & =\infty \end{array}$

Limit does not exist