This question applies the fundamental law of trigonometry and the sine/cosine addition and subtraction formulas.
sin(α+β)=sinαcosβ+cosαsinβ
sin(α−β)=sinαcosβ−cosαsinβ
cos(α+β)=cosαcosβ−sinαsinβ
cos(α−β)=cosαcosβ+sinαsinβ
Note: For cos(α±β), the sign between the terms is opposite to the operator between the angles.
When simplifying expressions of the form:
- sinAcosB+cosAsinB → recognise as sin(A+B)
- sinAcosB−cosAsinB → recognise as sin(A−B)
- cosAcosB−sinAsinB → recognise as cos(A+B)
- cosAcosB+sinAsinB → recognise as cos(A−B)
Simplify: sin138∘cos46∘−cos138∘sin46∘
Solution:
Recognise the pattern sinAcosB−cosAsinB=sin(A−B):
sin138∘cos46∘−cos138∘sin46∘=sin(138∘−46∘)=sin92∘