Exercise 3.1 — Question 5
This question draws on vectors in 3D space, including:
- The rectangular coordinate system in space (x, y, z axes)
- Unit vectors i^, j^, k^ along the x, y, z axes respectively
- Vector between two points: PQ=(x2−x1)i^+(y2−y1)j^+(z2−z1)k^
- Magnitude of a vector: ∣v∣=v12+v22+v32
- Parallel vectors: a∥b iff b1a1=b2a2=b3a3
Given points P(x1,y1,z1) and Q(x2,y2,z2):
PQ=OQ−OP=(x2−x1)i^+(y2−y1)j^+(z2−z1)k^
Note that QP=−PQ, illustrating the additive inverse property of vectors.
Vectors a=a1i^+a2j^+a3k^ and b=b1i^+b2j^+b3k^ are parallel if:
a=kbfor some scalar k=0
In component form:
b1a1=b2a2=b3a3
| Property | Statement |
|---|
| Commutative | a+b=b+a |
| Associative | (a+b)+c=a+(b+c) |
| Identity (Null vector) | a+0=a |
| Additive Inverse | a+(−a)=0 |
Given: P(1,2,−1) and Q(3,0,4). Find PQ, QP, and ∣PQ∣.
Step 1: Find PQ:
PQ=(3−1)i^+(0−2)j^+(4−(−1))k^=2i^−2j^+5k^
Step 2: Find QP:
QP=−PQ=−2i^+2j^−5k^
Step 3: Find ∣PQ∣:
∣PQ∣=(2)2+(−2)2+(5)2=4+4+25=33